In an ap the sum of first 10 terms is - 150
WebApr 8, 2024 · Hint: Sum of n terms of AP S n = n 2 [ 2 a + ( n − 1) d]. Given sum of first ten terms = − 150 We know that Sum of n terms of AP S n = n 2 [ 2 a + ( n − 1) d] Therefore, ⇒ … WebApr 11, 2024 · Given the sum of the first 10 terms of an AP is -150 and the sum of the next ten terms which means Sum of first 20 terms - Sum of first 10 terms is -530. Let the first term, common difference of the AP be a and d respectively. Now, ⇒ S₁₀ = 10/2 [ 2a + (10 - 1)d ] ⇒ -150 = 5 [ 2a + 9d ] ⇒ 2a + 9d = -30 ...(i) Now, according to the second case,
In an ap the sum of first 10 terms is - 150
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WebIf its 10th term is 41, then find the sum of its first fifteen terms. Solution: Question 33. The 13th term of an AP is four times its 3rd term. If its fifth term is 16, then find the sum of its first ten terms. Solution: Question 34. In an A.P., if the 12th term is -13 and the sum of its first four terms is 24, find the sum of its first ten terms. WebAnswer (1 of 5): 15+30+45 … +150 is an AP, whose first term, a = 15 and the common difference = 15. Tn = 150 = a+(n-1)d = 15 + (n-1)*15, or dividing right through by 15, 10 = 1 + (n-1), or n = 10 Sn = (n/2)[2a + (n-1)d] S10= (10/2)[2*15 + …
WebThe sum of the first five terms of an AP and the sum of the first seven terms of the same AP is 167. If the sum of the first ten terms of this AP is 235, find the sum of its first twenty terms. Q. WebOct 10, 2024 · The sum of the first five terms of an AP and the sum of the first seven terms of the same AP is 167. If the sum of the first ten terms of this AP is 235 , find the sum of its first twenty terms. If sum of first 6 terms of an AP is 36 and that of the first 16 terms is 256 , find the sum of first 10 terms.
WebFeb 17, 2024 · Sum of first 10 terms = -150. hence we have (10/2) [ 2a + 9d ] = -150 or 2a + 9d = -30 ..................... (1) next 10 terms gives total = -550 . Hence sum of 20 terms = -150 … WebApr 11, 2024 · In an AP. the sum of first ten terms is -150 and the sum of its next ten terms is -530 To Find :- AP Solution :- We know that Now, Putting S10 as -150 Second case …
WebApr 2, 2024 · The median of the distribution given below is 14.4. Find the values of x and y, if the sum of frequency is 20. Find the common difference ' d ' of an AP whose first term is 10 and the sum of the first 14 terms is 1505 . For what value of ' n ', are the nth terms of the APs : 9,7,5,….. and 15,12,9,…. the same?
WebMar 19, 2024 · Given that sum of the first 10 terms of an A.P. is -150. S10 = -150 And the sum of next 10 terms is -550. So, the sum of first 20 terms = Sum of first 10 terms + sum … curl command to check tls version of aksWebThe sum of n terms of an AP can be easily found out using a simple formula which says that, if we have an AP whose first term is a and the common difference is d, then the formula of the sum of n terms of the AP is S n = … curl command to check public ipWebApr 8, 2024 · SAN JOSE, Calif. (AP) — Connor McDavid became the first player in 27 years to reach 150 points in a season when he had a goal and an assist in the first period of Edmonton’s game against the … curl command to download chromeWebApr 15, 2024 · Best answer Let d be the common difference. Given: first term = a = -4 last term = l = 29 Sum of all the terms = Sn = 150 Sn = n/2 [a + l] 150 = n/2 [-4 + 29] n = 12 There are 12 terms in total. Therefore, 29 is the 12th term of the AP. Now, 29 = -4 + (12 – 1)d 29 = -4 + 11d d = 3 The common difference is 3. ← Prev Question Next Question → easy home fan aldicurl command to check website statusWebSep 2, 2024 · Best answer i. Sum of first five terms = 150 Sum of the five consecutive terms of arithmetic sequence is five times of its middle term. Third term = 150 5 = 30 150 5 = 30 ii. First term + Tenth term = Second term + Nineth term = Third term + Eighth term = Fourth term + Seventh term = Fifth term + Sixth term = 550 5 = 110 550 5 = 110 easy home fan-forced heaterWebYou would do the exact same process, but you would have to SOLVE for "n" (number of terms) first. To do so, you must start with the arithmetic sequence formula: tn = a + d(n −1) Then, sub in all known values. tn = 15 (last term of the sequence), a = 1 (first term), d = 2 (difference between terms) and solve for n like so: 15 = 1 + 2(n −1) easy home fan heater from aldi