WebExplanation: The oxidation number of S in PbSO 4=6 The oxidation number of S in PbS = −2 So, the oxidation number is changes from +6 in PbSO 4 to −2 in PbS. Thus , sulphur is reduced. The reaction is : PbSO 4+2C→PbS+2CO 2 Hence option A is correct answer Solve any question of Redox Reactions with:- Patterns of problems > Was this answer helpful? 0 Webthe oxidation numbers ? molecules are of neutral charge so we simply balance charges....the sum of the oxidation multiplied by the number of atoms of that particular …
In "PbS"(s) + 4"H"_2"O"_2(aq) -> "PbSO"_4(s) - Socratic.org
WebPbS (s)+4H2O2 (aq)→PbSO4 (s)+4H2O (l) The question is: Which element is oxidized and which is reduced in the following reactions? Express your answers as chemical symbols separated by a comma. Enter the oxidized element first. My question is: When finding the oxidation number of O, should you assume O has a charge of -2? WebNH4 is (+1) (Oxidation number of N in NH4+ is -3 Oxidation number of each H in NH4+ is +1) Ce is +3. SO4 is -2 ( Oxidation number of S is +6 and O is -2 in SO4) You have 2 polyatomic ions in this. NH4 and SO4. NH4 is +1 (you will probably have to memorize common ions and this is very common.) Since NH4 is +1 you can look at each element ... lowe\u0027s huber heights phone number
How do you find the oxidation numbers for PbSO4? I got Pb=+2 …
Web3 rows · The oxidation number of O in PbSO4 is -2. The oxidation number of S in PbSO4 is +6. The ... WebMar 15, 2016 · 2 You are correct, the Pb (s) is oxidized, which makes it the reducing agent. However, there is no change in the oxidation state of the H or the SO4−, so it is not the oxidizing agent. Rather the PbO2 (s) is the oxidizing agent, as the Pb goes from +4 in the PbO2 (s) to +2 in the PbSO4 (s). Share Improve this answer Follow Web0:00 / 1:49 How to find the Oxidation Number for S in MgSO4 (Magnesium sulfate) Wayne Breslyn 631K subscribers Subscribe 14K views 3 years ago To find the correct oxidation state of S in... japanese main character names